[Event "Benedict960: Benedict960 - 960 ways to switch sides."]
[Site "SchemingMind.com"]
[Date "2010.10.08"]
[Round "-"]
[White "lemme howdt"]
[Black "marble"]
[Result "1-0"]
[Variant "benedictrandom"]
[SetUp "1"]
[FEN "rkbqnbnr/pppppppp/8/8/8/8/PPPPPPPP/RKBQNBNR w KQkq - 0 1"]
[WhiteCountry "USA"]
[BlackCountry "ENG"]
[WhiteElo "1632"]
[WhiteRD "76"]
[BlackElo "1506"]
[BlackRD "76"]
[GameID "262952"]
1. e3
{
lemme howdt: number 710 shall be lucky for us - are you ready for 10/10/10 in three days?
}
1... e5
{
marble: I was not aware of it
}
2. Nd3 Bd6 3. Nc5
{
lemme howdt: i tend to be a numbers junkie
}
3... a6
{
marble: If you have an 8 figure number where the first 4 are the same as the second 4 e.g.43764376 then the number will always be divisible by the prime number 137 exactly. Can you work out why?
}
4. Ne6
{
lemme howdt: whoever worked out this problem originally had way too much time on their hands
}
4... Be7
{
marble: I did and it is very simple: I can explain it if you like
}
5. Qe2
{
lemme howdt: go for it
}
{
marble: The first four numbers are ten thousnd times the second four numbers and only two numbers go lnto ten thousand: one hundred and thirty seven and seventy three
}
5... Nd6
{
marble: Sorry ten thousand and one my computer will not let me print figures
}
6. a7
{
lemme howdt: yes - that prime plus one game - well done (and good game)
}
{
marble: Well played
}
1-0